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What is the equation of the line in slope intercept form using these points?

What Is The Equation Of The Line In Slope Intercept Form Using These Points class=

Sagot :

Answer:

y = -x - 1

Step-by-step explanation:

1. The slope-intercept form of any linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.

2. To find the slope given two points, we can use the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] and plug in the corresponding variable.

  • [tex]\frac{5-(-2)}{-6-1}[/tex]
  • [tex]\frac{5+2}{-7}[/tex]
  • [tex]\frac{7}{-7}[/tex]
  • [tex]-1[/tex]

3. Okay, so the slope is -1x or just -x. This means that the equation looks like this so far: y = -x + b

4. To find b, the y-intercept, we can take the equation of [tex]b = y_1 - m * x_1[/tex] and plug in the values!

  • [tex]b = -2-(-1)*1[/tex]
  • [tex]b = -2 + 1 * 1[/tex]
  • [tex]b = -1 * 1[/tex]
  • [tex]b = -1[/tex]

5. Now that we have our y-intercept and slope, let's plug in those values and find the equation!

  • [tex]y = -x - 1[/tex]

Therefore, the equation of the line is y = -x - 1. I hope this helped you!