Applying the formula for each identified shape that are given, the correct areas to each shape are:
a. Square = 134.6 sq. yd
b. Circle = 452.2 sq. cm
c. Parallelogram = 40.6 sq. cm
d. Rectangle = 43.2 sq. ft
e. Trapezium = 25.7 sq. m
f. Triangle = 21.6 sq. ft
a. The shape given is a square.
Area of the square = [tex]s^2[/tex]
Where,
s = 11.6 yd
Plug in the value of s
Area of the square = [tex]11.6^2 = 134.6 $ yd^2[/tex]
b. The shape given is a circle.
Area of the circle = [tex]\pi r^2[/tex]
r = 12 cm
Area of the square = [tex]\pi \times 12^2 = 452.2 $ cm^2[/tex]
c. The shape given is a parallelogram.
Area of the parallelogram = [tex]bh[/tex]
b = 7 cm
h = 5.8 cm
- Plug in the value of b and h
Area of the parallelogram = [tex]7 \times 5.8 = 40.6 $ cm^2[/tex]
d. The shape given is a rectangle.
Area of the rectangle = [tex]l \times w[/tex]
l = 8.3 ft
w = 5.2 ft
- Plug in the value of l and w
Area of the rectangle = [tex]8.3 \times 5.2 = 43.2 $ ft^2[/tex]
e. The shape given is a trapezium.
Area of the trapezium = [tex]\frac{1}{2} (a + b) \times h[/tex]
a = 2.8 m
b = 10.4 m
h = 3.9 m
- Plug in the value of a, b, and h
Area of the trapezium = [tex]\frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 $ m^2[/tex]
f. The shape given is a triangle. (See attachment for the shape).
Area of the triangle = [tex]\frac{1}{2} \times b \times h[/tex]
b = 9 ft
h = 4.8 ft
- Plug in the value of b, and h
Area of the triangle = [tex]\frac{1}{2} \times 9 \times 4.8 = 21.6 $ ft^2[/tex]
Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:
a. Square = 134.6 sq. yd
b. Circle = 452.2 sq. cm
c. Parallelogram = 40.6 sq. cm
d. Rectangle = 43.2 sq. ft
e. Trapezium = 25.7 sq. m
f. Triangle = 21.6 sq. ft
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