Answer:
The resultant force will be 5 N in the South West Direction.
Explanation:
Tip:
If we have two vectors A and B, their resultant is:
[tex]\boxed{ \mathsf{Resultant = A^2+B^2+2AB\:cos(\theta)}}[/tex]
[tex]\theta[/tex] is the angle between A and B
Since, Force is a vector quantity, the answer to he given diagram will be thought out by Vector Laws of Addition.
Solution:
6N and 9N are in opposite directions, so their resultant will simply be their difference, and it will be pointing in the direction of the vector with larger magnitude.
= 9 - 6
= 3 N
Now, we have two vectors. one of magnitude 4N pointing towards West and the other of magnitude 3N pointing towards South.
- They're at an angle of 90°. ([tex]\theta[/tex]=90)
- Their resultant will lie in between the two vectors, 4N and 3N.(The South West Direction).
It's magnitude will be equal to [tex]\mathsf{\red{ \sqrt{4^{2} +3^{2} } }}[/tex]
(as cos90=0, we're left with the sum of the squares of the two vectors)
= 5N
Therefore, the resultant force will be 5N towards the South-West.
