lovelanguage89
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Find 2 integers whose sum is 16 and the product is 80

Sagot :

bosm93

Answer:

No solution in real numbers

Step-by-step explanation:

a+b=16

a*b=80

Unfortunately it does not have solution

chronos14

Answer:

I think the question is mistyping or wrong

Step-by-step explanation:

A+B=16

A*B = -80

Convert to

A=16-B

Substitute

(16-B)*B=-80

16B-B^2+80=0

Change the sign to make it easier (multiply by negative number)

B^2 -16B-80

=(B - 4)(B + 20)

B1=-4 and B2=20

Then its match if the product is -80.

Or second option is, assuming that the sum is 18, not 16

The A would be 8 and the B would be 10

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.