Answered

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You throw a ball upwards at 22.0 m/s how high will it go?

Sagot :

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t ′ )

2

t

′

=3s

Total time= 3+2= 5s

Explanation:

TAKE 22.0 IN PLACE OF 20 U WILL GET YR ANSWER

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