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Sagot :
To answer this question we need to make use of Linear Programming
The solution is:
x = 170 units
y = 345 units
z(max) = 2235 rupees
To solve a linear programming problem, we need to formulate the model
The Objective Function
Let´s call x the number of product 1 manufactured
and y the number of product 2 manufactured
Then the Objective Function is:
z = 3× x + 5×y to be maximize
The set of constraints are:
D1 D2
( min. ) ( min. )
Product 1 (x) 1 3
Product 2 (y) 2 2
Availability 860 1200
First constraint:
Time available in D1: 860 minutes
1×x + 2×y ≤ 860
Second constraint:
Time available in D2: 1200 minutes
3×x + 2×y ≤ 1200
General constraint: x ≥ 0 ; y ≥ 0 integers ( we will assume only complete products at the end of the period no fractions )
Then the model is:
z = 3× x + 5×y to be maximize
Subject to:
1×x + 2×y ≤ 860
3×x + 2×y ≤ 1200
x ≥0 y ≥ 0 integers
With the help of AtoZmath we get the solution:
x = 170 units
y = 345 units
z(max) = 2235 rupies
Related Link: https://brainly.com/question/15319802
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