graces4891
Answered

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A 2,500 kg car has an applied force of 2,500 N but iss experience 200 N of friction from the road and 320 N of air resistance. What was the acceleration of the car?

Sagot :

Anonimity

Explanation:

is known :

  • m = 2,500 kg
  • F₁ = 2,500 N
  • F₂ = 200 N
  • F₃ = 320 N

Asked :

a =…?

Answer :

F = m · a

(2,500 - 200 - 320) = 2,500m

1,980 = 2,500a

a = 1,980 ÷ 2,500

a = 0,792 m/s²

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