Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

what is the 8th term of the sequence whose first term is 64 and common ratio is 1/2?

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

Here's the solution :

  • [tex]nth \: \: term = ar {}^{n - 1} [/tex]

here,

  • n = 8th term

  • r = 1/2

  • a = 64

now, let's find the 8th term :

  • [tex]64 \times { \bigg( \dfrac{1}{2} \bigg ) }^{8 - 1} [/tex]

  • [tex]64 \times \bigg(\dfrac{1}{2 {}^{7} } \bigg)[/tex]

  • [tex]64 \times \dfrac{1}{128} [/tex]

  • [tex] \dfrac{1}{2} \: \: \: o r \: \: \: 0.5[/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.