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Sagot :
Answer:
1,7,13,19,.......
where a=1 & d=6(a2-a1=7-1=6)
an=a+(n-1)d
an=1+(n-1)6 [a=1,d=6]
an=1+6n-6
an=6n-5
6n-5 is the nth term of this sequence
Step-by-step explanation:
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The sequence is defined by the expression:
A(n)=6(n-1)-5
so, A(35) = 6(35-1) -5 = 204 - 5 = 199
The 35th term is 199.
A(n)=6(n-1)-5
so, A(35) = 6(35-1) -5 = 204 - 5 = 199
The 35th term is 199.
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