Answered

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Minimum value of y when y = x^2 - 3x - 1

Sagot :

Mahlex

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Answer:

- 3.25

Step-by-step explanation:

x² - 3x - 1 = (x² - 3x + (3/2)²) - (9/4 + 1)

               = (x - 3/2)² - 13/4

parabola: y = (x-h)² + k      (h,k): vertex

vertex: (3/2 , -13/4) or (1.5 , - 3.25)

Minimum value of y : - 3.25

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