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A rock thrown with a velocity of 23.7 m/s horizontally off the top of a bridge falls 120 m to the water below. How far away does the rock land?

Sagot :

jesseling111

Answer:

d=117.2845834m

Explanation:

Let's start out with the vertical components

vi=0, vf=?, a=9.8, x=120, t=?

Let's find how long the rock was falling.

x=vi*t+.5*a*t^2

120=0+.5*9.8*t^2

120=4.9*t^2

t=4.9487166s

Since we know the horizontal velocity is constant, we use the formula v=d/t

23.7=d/4.9487166

d=117.2845834m

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