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Write a Pythagorean triplet whose smallest number is 8​

Sagot :

Answer:

(8,15,17)

Step-by-step explanation:

Lets verify

[tex]\\ \sf\longmapsto 8^2+15^2=17^2[/tex]

[tex]\\ \sf\longmapsto 64+225=289[/tex]

[tex]\\ \sf\longmapsto 289=289[/tex]

Hence verified

mhanifa

Answer:

  • 8, 15, 17

Step-by-step explanation:

Pythagorean triplets are a, b and c with property of:

  • a² + b² = c², where a, b, c are different positive integers

Let a = 8, find b and c.

The we have:

  • 8² + b² = c²
  • c² - b² = 64
  • (c + b)(c - b) = 64

Options:

64 = 64*1 = 32*2 = 16*4 = 8*8

1)

  • c + b = 64
  • c - b = 1

Add up to get:

  • 2c = 65 ⇒ c = 32.5 - is not an integer, no solution

2)

  • c + b = 32
  • c - b = 2

Add up to get:

  • 2c = 34
  • c = 17 ⇒ b = 15

The triplet is 8, 15, 17

3)

  • c + b = 16
  • c - b = 4

Add up to get:

  • 2c = 20
  • c = 10 ⇒ b = 6 < 8, b is smaller than 8, no solution

4)

  • c + b = 8
  • c - b = 8

Add up to get:

  • 2c = 16
  • c = 8 ⇒ b = 0, no triplet, no solution
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