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Sagot :
Answer:
- ₹ 3060.40
Step-by-step explanation:
Given:
- Principal P = ₹ 50000
- Interest rate r = 8% PA
- Time t = 9 months = 9*1/12 years = 3/4 years
- Number of compounds per year n = 4
The amount of interest:
- [tex]I = P*(1+r/n)^{nt} - P[/tex]
- [tex]I = 50000*(1+8/4*1/100)^{4*3/4}-50000= 3060.40[/tex]
Answer:
Rs. 3060.4
Step-by-step explanation:
[tex]\sf{ A = P \times (1 + \frac{r}{n})^{nt} }[/tex]
[tex]\sf{ A = 50000 \times (1 + \frac{8}{4} \times \frac{1}{100} )^{4 \times \frac{3}{4}} }[/tex]
[tex]\sf{ A =53060.4 }[/tex]
.
compound interest
[tex]\sf{ Ci = A - P}[/tex]
[tex]\sf{ Ci = 53060.4 - 50000}[/tex]
[tex]\sf{ Ci = 3060.4 }[/tex]
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