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Sagot :
(a) The total displacement is zero
(b) The average velocity from the grocery store to the post office is 11 m/s.
(c) The average speed of the entire trip is 9.71 m/s
The given parameters;
- initial position = 180 m at store
- final position = 330 m at post office
- time for the forward trip = 45 s
- time for the backward trip = 60 s
(a) The total displacement is the change in his position;
Displacement = forward position - backward position
Displacement = 510 m - 510 m = 0
(b) The average velocity from the grocery store to the post office;
Displacement = 510 m - 180 m = 330 m
Time of motion from his home to grocery store, = (60 - 45) = 15 s
Time of motion to post office = 45 s - 15 s = 30 s
[tex]average \ velocity = \frac{330}{30} = 11 \ m/s[/tex]
(c) The average speed of the entire trip;
total distance = 510 m forward + 510 m backward = 1020 m
total time = 45 s + 60 s = 105 s
[tex]average \ speed = \frac{1020}{105} \\\\average \ speed = 9.71 \ m/s[/tex]
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