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Determine the standard form of the equation of the line that passes through (-6,6) and (3, -2)

Sagot :

s1m1

Answer:

 (8/9)x +y = (2/3)

Step-by-step explanation:

General standard form of an equation of a line is y = mx+b, where m is the slope of the line and b is the y-intercept ( where the line intersects the y-axis.)

For points (-6, 6) and (3, -2)

m= (y2-y1)/(x2-x1) = (-2-6) / (3-(-6)) = -8 / 9

y = (-8/9)x +b

Substitute any of the 2 points to find b. If we choose (x=3, y= -2) then

-2 = (-8/9)*3 +b, simplify (-8*3)/9

-2 = (-8/3)+b, add (8/3) to both sides

-2+(8/3) = b, find the common  denominator and add the fractions

(-6+8)/3 =b

2/3 =b

The standard form of the equation of the line that passes through (-6,6) and (3, -2) is (8/9)x + y = (2/3)

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