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Sagot :
1) The total Taguchi Quality Cost is;
L_total = $119.2
2) The recommendation for Mary Beth Mars because;
She should focus more on the parking/drive complaints, pool complaints and grounds complaints.
Problem 1;
We are given that;
Dimension of length to be cut; D_i = 74 mm
Dimension of Length of upper spec limit; D_u = 78.5 mm
Dimension of Length of lower spec limit; D_l = 69.5 mm
Cost at which metal must be scrapped; L = $42
Let's find the unit formula to find cost for each of the 5 units sample.
T = L/(D_i - D_l)²
Plugging in the relevant values, we have;
T = 42/(74 - 69.5)²
T = 42/20.25
T = 2.074
Thus, the cost for each of the 5 units would be gotten from the formula;
L = 2.074(D_i - D_l)²
The measurement of each sample was given as;
75.6mm, 78.2mm, 68.7mm, 71.0mm and 73.6 mm.
Thus;
L₁ = 2.074(D_i - D_1)²
L₁ = 2.074(74 - 75.6)²
L₁ = $5.3094
Problem 1;
We are given that;
Dimension of length to be cut; D_i = 74 mm
Dimension of Length of upper spec limit; D_u = 78.5 mm
Dimension of Length of lower spec limit; D_l = 69.5 mm
Cost at which metal must be scrapped; L = $42
Let's find the unit formula to find cost for each of the 5 units sample.
T = L/(D_i - D_l)²
Plugging in the relevant values, we have;
T = 42/(74 - 69.5)²
T = 42/20.25
T = 2.074
Thus, the cost for each of the 5 units would be gotten from the formula;
L = 2.074(D_i - D_l)²
The measurement of each sample was given as;
75.6mm, 78.2mm, 68.7mm, 71.0mm and 73.6 mm.
Thus;
L₁ = 2.074(D_i - D_1)²
L₁ = 2.074(74 - 75.6)²
L₁ = $5.30944
L₂ = 2.074(74 - 78.2)²
L₂ = $36.58536
L₃ = 2.074(74 - 68.7)²
L₃ = $58.25866
L₄ = 2.074(74 - 71)²
L₄ = $18.666
L₅ = 2.074(74 - 73.6)²
L₅ = $0.33184
Total Taguchi Quality Cost = L₁ + L₂ + L₃ + L₄ + L₅
Total Taguchi Quality Cost = $5.30944 + $36.58536 + $58.25866 + $18.666 + $0.33184
Total Taguchi Quality Cost = $119.1513
Approximating to the nearest penny gives;
Total Taguchi Quality Cost = $119.2
Problem 2;
The check sheet she has kept for the past 12 weeks is missing and so i have attached it.
From the check sheet attached we can see that;
Frequency of parking/drive complaints = 30
Frequency of pool complaints = 20
Frequency of grounds complaints = 17
Frequency of Tenant issues complaints = 14
Frequency of Electric/plumbing complaints = 5
With those frequencies, i have drawn a pareto's chart and attached it.
Pareto's chart is a bar graph that helps us to understand what is the priority per time. We can see from the chart that the complaint with the highest frequency is that of parking/drive which makes up around 34.88%. Then pool complaints which is 23.26% and then ground complaints which consists of 19.77%.
This 3 complaints add up to about approximately 78% which is close to 80% and thus Mary Beth Marrs is recommended to focus on these 3 issues primarily according to pareto's principle.
Read more at; https://brainly.com/question/17989104
![View image AFOKE88](https://us-static.z-dn.net/files/d2b/7a12a8be147b6b3e1e47791ca46aae88.jpg)
![View image AFOKE88](https://us-static.z-dn.net/files/d89/c508b4ad58ac59f479fee829c8004307.jpg)
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