Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

At noon, Shawn starts walking due north at a rate of s miles per hour. Starting from the

same point 2 hours later, his friend Max starts walking due east at the rate of m miles

per hour. At 5 p.m. that same day, Shawn and Max are 17 miles apart.

Create an equation (using the word bank) that represents the relationship between the

rates the boys walked, in miles per hour, and the given distance between them.

Word Bank:

3m

5m

35

5s

1

17

289

1)2+(

)2 =


Sagot :

The sum of two vectors that are at right angles to each other is given by Pythagoras's

The equation that gives the relationship between the rates the boys walks and the distance between them is given as follows;

289 = 25·s² + 9·m²

Reason:

Known;

Rate at which Shawn starts walking due North = s miles per hour

Time Shawn starts walking North = 12 noon

Rate at which Max starts walking East 2 hours later = m miles per hour

The distance between Shawn and Max at 5 p.m. the same day, d = 17 miles

Required:

To create an equation representing the relationship between the rates the boys walked, in miles per hour and the given distance between them

Solution;

The total distance North Shawn walked, S = 5·s miles

The total distance East Max walked, M = 3·m miles

The distance between them is given by Pythagoras's theorem as follows;

d² = S² + M²

By plugging in the values, we get;

17² = (5·s)² + (3·m)² = 25·s² + 9·m²

The equation representing the relationship between the rates the boys walked, in miles per hour and the distance between them is therefore;

289 = 25·s² + 9·m²

Learn more here:

https://brainly.com/question/10426077