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1. If m∠5 = 42° and m∠1 = 117°, find m∠CDF.
2. Question 7 options:
If m∠3=73° and DG−→−⊥DF−→− find m∠FDE
3. In the diagram below, BC−→− bisects ∠FBE
If m∠ABF=(7x+20)°, m∠FBC=(2x−5)° and m∠ABC=159°, find the value of x.
4. In the diagram below, BC−→− bisects ∠FBE
If m∠DBC=(12x−3)°, m∠DBE=(5x+12)°, and m∠EBC=(3x+13)°, find m∠EBC
5. In the diagram below, BC−→− bisects ∠FBE
If m∠FBC=(10x−9)°, m∠CBE=(4x+15)°,find m∠FBE.

Please Help 1 If M5 42 And M1 117 Find MCDF 2 Question 7 Options If M373 And DGDF Find MFDE 3 In The Diagram Below BC Bisects FBE If MABF7x20 MFBC2x5 And MABC15 class=
Please Help 1 If M5 42 And M1 117 Find MCDF 2 Question 7 Options If M373 And DGDF Find MFDE 3 In The Diagram Below BC Bisects FBE If MABF7x20 MFBC2x5 And MABC15 class=
Please Help 1 If M5 42 And M1 117 Find MCDF 2 Question 7 Options If M373 And DGDF Find MFDE 3 In The Diagram Below BC Bisects FBE If MABF7x20 MFBC2x5 And MABC15 class=
Please Help 1 If M5 42 And M1 117 Find MCDF 2 Question 7 Options If M373 And DGDF Find MFDE 3 In The Diagram Below BC Bisects FBE If MABF7x20 MFBC2x5 And MABC15 class=
Please Help 1 If M5 42 And M1 117 Find MCDF 2 Question 7 Options If M373 And DGDF Find MFDE 3 In The Diagram Below BC Bisects FBE If MABF7x20 MFBC2x5 And MABC15 class=

Sagot :

mhanifa

Answer:

  • See below

Step-by-step explanation:

#1

  • m∠CDF = m∠5 + m∠1 = 42° + 117° = 159°

#2

  • m∠FDE = m∠FDG - m∠3 = 90° - 73° = 17°

#3

m∠ABC = m∠ABF + ∠mFBC

  • 159 = 7x + 20 + 2x - 5
  • 159 = 9x + 15
  • 9x = 159 - 15
  • 9x = 144
  • x = 144/9
  • x = 16

#4

m∠EBC = m∠DBC - m∠DBE

  • 3x + 13 = 12x - 3 - 5x - 12
  • 3x + 13 = 7x - 15
  • 7x - 3x = 13 + 15
  • 4x = 28
  • x = 7

m∠EBC = 3*7 + 13 = 21 + 13 = 34°

#5

m∠FBE = m∠FBC + m∠CBE and m∠FBC = m∠CBE

m∠FBE = 2m∠CBE

  • 10x - 9 = 4x + 15
  • 10x - 4x = 15 + 9
  • 6x = 24
  • x = 4

m∠FBE = 2*(4*4 + 15) = 2*31 = 62°

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