williamgriffiths19
Answered

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Find the value of A that makes the following equation true for all values of x. (1/3)^-9x = A^x

Sagot :

kamilmatematik100504

Answer:  [tex]\large \boldsymbol {A=19683}[/tex]

Step-by-step explanation:

[tex]\large \boldsymbol {} \displaystyle \bigg( \frac{1}{3} \bigg)^{-9x}=A^x \\\\\\ (3^{-1})^{-9x} =A^x \\\\\\( 3^{9} )^x=A^x \\\\\\ A=3^9=19683[/tex]

ItzMeÆXO

Answer:

3⁹

Step-by-step explanation:

[tex]\sf{(\frac{1}{3})^{-9x} = A^{x} }[/tex]

[tex]\sf{(3^{-1})^{-9x} = A^{x} }[/tex]

[tex]\sf{3^{9x} = A^{x} }[/tex]

[tex]\sf{\boxed{A = 3^9 }}[/tex]

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