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Sagot :
Let x be the yearly salary of an architect. Then the yearly salary of a lawyer is 2x-20000.
We can build an equation now! x+(2x-20000)=211000, because the yearly salary of an architect plus the yearly salary of a lawyer is 211000.
We combine like terms to get 3x-20000=211000.
We add 20000 to both sides to get 3x=231000.
We divide both sides by 3 to get x=77000, so the average yearly salary of a lawyer is 77000.
Then, the average yearly salary of an architect is 2(77000)-20000=154000-20000=134000, so the average yearly salary of an architect is 134000.
Architect salary be x and lawyer's salary be 2x-20
Now
- x+2x-20=211
- 3x-20=211
- 3x=231
- x=$77K
- 2x-20=$134K
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