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Sagot :
Hi there!
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I believe your answer is:
c < 2
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Here’s why:
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[tex]c+6>5c - 2\\--------------\\\\\rightarrow5c - 2< c + 6 \leftarrow \text{Notice how the sides are switched.}\\\\\rightarrow 5c - c -2 < c - c + 6\\\\\rightarrow 4c -2 < 6\\\\\rightarrow 4c - 2 + 2 < 6 + 2\\\\\rightarrow 4c < 8\\\\\rightarrow \frac{4c<8}{4}\\\\\rightarrow \boxed{c < 2}[/tex]
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Hope this helps you. I apologize if it’s incorrect.
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