Korimo2289
Answered

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A scuba diver dove from the surface of the ocean to an elevation of −49 9/10 feet at a rate of −11.1 feet per minute. After spending 14.75 minutes at that elevation, the diver ascended to an elevation of −18 9/10 feet. The total time for the dive so far was 21 1/8minutes. What was the rate of change in the diver's elevation during the ascent? Round your answer to the nearest hundredth.

Sagot :

descent time: 4.25 min
hover time: 12.75 min
19.125 - 4.25-12.75 = 2.125 min

So, the ascent rate was (-28.9 - (-79.9))ft/2.125min = 24.0 ft/min
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