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What is the equation of the line that passes through the point (5,−2) and has a slope of 6/5?

Sagot :

Answer:

y = 6/5x - 8

Step-by-step explanation:

slope-line equation : y = mx + b

slope is 6/5

Let's find the y-intercept using (5, -2)

y = mx + b

-2 = 6/5(5) + b

-2 = 30/5 + b

-2 = 6 + b

-6    -6

---------------------

-8 = b

So, y = 6/5x - 8 is your equation.

Answer:

y = [tex]\frac{6}{5}[/tex] x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = [tex]\frac{6}{5}[/tex] , then

y = [tex]\frac{6}{5}[/tex] x + c ← is the partial equation

To find c substitute (5, - 2 ) into the partial equation

- 2 = 6 + c ⇒ c = - 2 - 6 = - 8

y = [tex]\frac{6}{5}[/tex] x - 8 ← equation of line

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