Answered

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Karl Schwartz had total travel expenses of $643. His transportation cost $290, lodging cost $198, and additional costs were $80. If dinner cost twice as much as lunch, how much was his lunch?

A
$10

B
$20

C
$25

D
$50

Sagot :

Karl Schwartz's lunch cost $25

Karl Schwartz total travel expenses comprises of transportation cost, lodging cost, dinner cost, lunch and additional cost.

In order to determine the cost of lunch, the first step is to determine the total cost of dinner and lunch.

Cost of lunch and dinner = total travelling expenses - sum of costs

$643 - ($290 + $198 +$80)

$643 - $568

Cost of lunch and dinner = $75

Let x represent the cost of lunch

cost of dinner = 2x

2x +x = 75

3x = 75

x = $25

A similar question was solved here: https://brainly.com/question/11492053?referrer=searchResults

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