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convert 1-√3i into polar form​

Sagot :

The polar form of 1-√3i  is [tex]4(cos 60 + isin60)[/tex]

For a complex number of the form:

z  =  x  +  iy

The polar form is of the form:

z  = r (cosθ + i sinθ)

For the complex number:

1-√3i

[tex]r = \sqrt{x^2+y^2} \\r = \sqrt{1^2+(-\sqrt{3})^2 } \\r = \sqrt{1+3} \\r = \sqrt{4} \\r = 2[/tex]

[tex]\theta = tan^{-1}}\frac{-\sqrt{3} }{1} \\\theta = tan^{-1}}\sqrt{3} \\\theta = 60^0[/tex]

The polar form of the equation is therefore:

[tex]z = 4(cos 60 + isin60)[/tex]

Learn more here: https://brainly.com/question/10337591

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