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The cup on the 9th hole of a golf course is located dead center in the middle of a circular green which is 30 feet in radius. Your ball is located as in the picture below. The ball follows a straight line path and exits the green at the right-most edge. Assume the ball travels 12 ft/sec. Introduce coordinates so that the cup is the origin of an xy-coordinate system. Provide numerical answers below with two decimal places of accuracy.
(a) The x-coordinate of the position where the ball enters the green will be
(b) The ball will exit the green exactly
(c) Suppose that L is a line tangent to the boundary of the golf green and parallel to the path of the ball. Let Q be the point where the line is tangent to the circle. Notice that there are two possible positions for Q. Find the possible x-coordinates of Q:

Sagot :

Roqhayakhazi
Same I need help with this

Answer:

Step-by-step explanation:

12ft p/s travels 30 ft radius

time = 30/12 = 2.5 seconds.

For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-30) and (0,0). Therefore, the slope is:

(-40-0)/(-30-0) = 40/30 = 1 1/3 = 1.333...4 multiplier

perpendicular tangent = -1 x 1/ 1.3334=-0.749962502

you cna change 40 to the height as I cannot see your picture you then reapply to the -1 x 1/ ?  type in multiplier here and you get your answer.

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