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devishri1977

Answer:

Step-by-step explanation:

Quadratic equation: ax² +bx + c = 0

D = b² - 4ac

1) 4x² - 3x - 2 = 0

a = 4  ; b = -3  ; c = -2

D = (-3)² - 4*4*(-2)

   = 9  + 32

    = 41

D > 0, So, two distinct real roots.

2) 5x² + 2x - 3 = 0

a = 5 ; b = 2 ; c = -3

D = 2² - 4*5*(-3)

 = 4 + 60

 = 64

D >0 . So, two distinct real roots.

3)9x² - 6x + 1 = 0

a = 9 ; b = -6 ;c =1

D = (-6)² - 4*9*1

  = 36 - 36

  = 0

D = 0.  So, two equal real roots.

4)3x² + 7x + 8 = 0

a = 3 ; b = 7 ; c = 8

D = 7² - 4*3*8

   = 49 - 96

  = - 47

D < 0 .So, two roots are complex and different.

5) 8x² + 5x = 0

a = 8 ; b = 5 ;  c = 0

D = 5² - 4*8*0

  = 25 - 0

 = 25

D > 0. So, two distinct real roots.

djtwinx017

Answer:

Attached are the solutions to the given table.

One thing to remember about Quadratic Formula and Discriminants:

  • if b² - 4ac = 0, then the equation has one real root.
  • if b² - 4ac > 0, then the equation have two real roots.
  • if b² - 4ac < 0, then the equation  have two complex roots.
View image djtwinx017
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