Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

need an answer, please need an answer, please​

Need An Answer Please Need An Answer Please class=

Sagot :

devishri1977

Answer:

Step-by-step explanation:

Quadratic equation: ax² +bx + c = 0

D = b² - 4ac

1) 4x² - 3x - 2 = 0

a = 4  ; b = -3  ; c = -2

D = (-3)² - 4*4*(-2)

   = 9  + 32

    = 41

D > 0, So, two distinct real roots.

2) 5x² + 2x - 3 = 0

a = 5 ; b = 2 ; c = -3

D = 2² - 4*5*(-3)

 = 4 + 60

 = 64

D >0 . So, two distinct real roots.

3)9x² - 6x + 1 = 0

a = 9 ; b = -6 ;c =1

D = (-6)² - 4*9*1

  = 36 - 36

  = 0

D = 0.  So, two equal real roots.

4)3x² + 7x + 8 = 0

a = 3 ; b = 7 ; c = 8

D = 7² - 4*3*8

   = 49 - 96

  = - 47

D < 0 .So, two roots are complex and different.

5) 8x² + 5x = 0

a = 8 ; b = 5 ;  c = 0

D = 5² - 4*8*0

  = 25 - 0

 = 25

D > 0. So, two distinct real roots.

djtwinx017

Answer:

Attached are the solutions to the given table.

One thing to remember about Quadratic Formula and Discriminants:

  • if b² - 4ac = 0, then the equation has one real root.
  • if b² - 4ac > 0, then the equation have two real roots.
  • if b² - 4ac < 0, then the equation  have two complex roots.
View image djtwinx017
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.