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A car traveling 11.00 m/s passes a marker reading 15 km. The car then accelerates with an average acceleration of 0.10 m/s 2 for 1 min. At approximately what marker is the car after 1.0 min?

Sagot :

Lanuel

The car would be at the marker reading 15.84 kilometers.

Given the following data:

  • Initial velocity = 11.0 m/s
  • Acceleration = 0.1 [tex]m/s^2[/tex]
  • Time = 1 minute

To find the distance covered by the car after 1.0 minute, we would use the second equation of motion:

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2} at^2[/tex]

Where:

  • S is the displacement or distance covered.
  • u is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

First of all, we would convert the time in minute to seconds.

Conversion:

1 minute = 60 seconds.

Substituting the given parameters into the formula, we have;

[tex]S = 11(60) + \frac{1}{2} (0.1)(60)^2\\\\S = 660 + 0.05(3600)\\\\S = 660 + 180[/tex]

Distance, S = 840 meters.

[tex]Kilometer = \frac{840}{1000} = 0.84 \; km[/tex]

New marker = Old marker + Distance

New marker = 15 + 0.84

New marker = 15.84 km

Therefore, the car would be at the marker reading 15.84 kilometers.

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