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discipulus

Answer:

[tex](x - 6)(x + 5) = {x}^{2} - x - 30 \\ or \\ a {x}^{2} + bx + c\\ {x}^{2} +( x_{1} + x_{2}) x + x_{1} .x_{2} \\ b = x_{1} + x_{2} = 5 - 6 = - 1 \\c = x_{1} .x_{2} = - 6 \times 5 = - 30 \\ \therefore \: {x}^{2} - x - 30[/tex]

you do the rest

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