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#1. Boyle's Law. A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L.
What is the pressure in the container if the temperature remains constant? (Answer is 6.8 kPa).

I NEED TO FIND HOW YOU GET TO THAT ANSWER

Sagot :

Lanuel

The final pressure in the container if the temperature remains constant is 68.3 kPa.

Given the following data;

  • Initial volume, V1 = 4.0 liters
  • Initial pressure, P1 = 205 kPa
  • Final volume, V2 = 12.0 Liters

To find the final pressure in the container if the temperature remains constant, we would use Boyle's Law:

Mathematically, Boyle's law is given by the formula;

[tex]P_1V_1 = P_2V_2[/tex]

Where;

  • P1 is the original (initial) pressure.
  • P2 is the final pressure.
  • V1 is the original (initial) volume.
  • V2 is the final volume.

Substituting the values into the formula, we have;

[tex]205[/tex] × [tex]4 =[/tex] [tex]12P_2[/tex]

[tex]820 = 12P_2\\\\P_2 = \frac{820}{12}[/tex]

Final pressure, P2 = 68.3 kPa

Therefore, the final pressure in the container if the temperature remains constant is 68.3 kPa.

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