Answered

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what is the slope of all lines parallel to the line 4x-5y+-1?

a -5/4

b 5/4

c-1/5

d4/5

Sagot :

VirαtKσhli

Given equation of the line ,

[tex]\implies 4x - 5y +(-1) = 0 [/tex]

Simplify ,

[tex]\implies 4x - 5y - 1 = 0 [/tex]

Transpose terms to RHS ,

[tex]\implies 5y = 4x - 1 [/tex]

Divide both sides by 5 ,

[tex]\implies \boxed{ y =\dfrac{4}{5}x -\dfrac{1}{5}}[/tex]

Now we know the slope intercept form of the line as [tex] y = mx + c [/tex] we have ,

  • [tex] m =\dfrac{4}{5}[/tex]

As we know that the slope of all parallel lines are same . Henceforth ,

  • [tex] m_{|| \ lines } =\dfrac{4}{5}[/tex]
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