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Sagot :
Answer:
Correct option is
B
(1−3a−3b)(1+a+b)
1−2a−2b−3(a+b)
2
=−3(a+b)
2
−2(a+b)+1
=−3(a+b)
2
−3(a+b)+(a+b)+1
=−3(a+b)((a+b)+1)+((a+b)+1)
=((a+b)+1)(1−3(a+b))
=(a+b+1)(1−3a−3b)
Answer:
[tex]-3.5[/tex]
Step-by-step explanation:
[tex](a-2b)^{3} \\=a^{3}-6a^{2} b+6ab^{2}-8b^{3}[/tex]
Given that,
[tex]a=(-3)\\b=(-1/2)[/tex]
So,
[tex](a-2b)^{3} \\=a^{3}-6a^{2} b+6ab^{2}-8b^{3}\\=(-3)^{3}-6* (-3)^{2} *\frac{-1}{2} +6*(-3)*(\frac{-1}{2} )^{2} -8*(\frac{-1}{2} )^{3} \\= (-27)-6*9*\frac{-1}{2} +-18*\frac{1}{4} -8*\frac{-1}{8} \\=(-27)-6*-4.5-4.5+1\\=-27+27-4.5+1\\=-3.5[/tex]
Hope this helps you
Let me know if you have any other questions :-)
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