Answer:
Explanation:
A classic projectile motion question. Horizontal motion does not matter whatsoever in the context of this equation as we are looking at the vertical component of velocity only. Since the question states that it is fired horizontally, there is no vertical component of velocity. Thus, v0y = 0.
Assuming the projectile is on the Earth, we can use the free-fall acceleration, 9.8 m/s^2.
The question gives us Δy, which is 37.3m.
Using the second kinematics equation, Δy = v0t + (at^2)/2, we can substitute in the values.
37.3 = 0 + 0.5(9.8)t^2
37.3 = 4.9t^2
7.61224489796 = t^2
t = 2.75902970226 seconds.
