jjaywalls
Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Karen wanted to cut three lengths of wood from a 10 foot long board. The length of three pieces she wanted to were 1 2/3 feet 2 3/4 feet and 3 5/6 feet

Sagot :

[tex]\\ \sf\longmapsto 1\dfrac{2}{3}+2\dfrac{3}{4}+3\dfrac{5}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{3}+\dfrac{11}{4}+\dfrac{23}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{20+33+46}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{99}{12}[/tex]

[tex]\\ \sf\longmapsto 8.2ft[/tex]

Rope left

[tex]\\ \sf\longmapsto 10-8.2=1.8ft[/tex]

UserIndonesia

Answer:

1¾ ft ≈ 1,75 ft

Step-by-step explanation:

[tex] \sf 1\frac{2}{3} + 2 \frac{3}{4} + 3\frac{5}{6} [/tex]

[tex] \sf = \frac{3 + 2}{3} + \frac{4 \times 2 + 3}{4} + \frac{6 \times 3 + 5}{6} [/tex]

[tex] = \sf \frac{5}{3} + \frac{11}{4} + \frac{23}{6} [/tex]

[tex] \sf = \frac{5 \times 4 + 11 \times 3}{3 \times 4} + \frac{23}{6} [/tex]

[tex] = \sf \frac{20 +33 }{12} + \frac{23}{6} [/tex]

[tex] \sf = \frac{53}{12} + \frac{23}{6} [/tex]

[tex] = \sf \frac{53}{12} + \frac{23 \times 2}{6 \times 2} [/tex]

[tex] \sf = \frac{53}{12} + \frac{46}{12} [/tex]

[tex] \sf = \frac{99}{12} [/tex]

[tex] \sf = \frac{10}{1} - \frac{99}{12} [/tex]

[tex] \sf = \frac{10 \times 12 - 99}{12} [/tex]

[tex] = \sf \frac{120 - 99}{12} [/tex]

[tex] \sf = \frac{21}{12} [/tex]

= 1¾ ft ≈ 1,75 ft

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.