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Sagot :
[tex]\longrightarrow{\mathfrak{\frac{-9}{6}÷\frac{3}{-2}}}[/tex]
[tex]\longrightarrow{\sf{\frac{-\cancel{9}}{\cancel{6}}\times\frac{-\cancel{2}}{\cancel{3}}}}[/tex]
[tex]\longrightarrow{\sf{\frac{3}{3}}}[/tex]
[tex]\longrightarrow{\boxed{\bf{1}}}[/tex]
Identity applied -
[tex]\star{\:\:\:\:\:\:\boxed{\bf{\frac{a}{b}÷\frac{c}{d}=\frac{a}{b}\times\frac{d}{c}}}}[/tex]
The answer is B
When dividing fractions you flip the numerator and the denominator of the first fraction making it go from -9/6 to 6/-9 then you multiply the fractions across, in the end the answer is 1 whole
When dividing fractions you flip the numerator and the denominator of the first fraction making it go from -9/6 to 6/-9 then you multiply the fractions across, in the end the answer is 1 whole
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