Answered

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First four terms
f(n)=n^3-n^2+1

Sagot :

cdj8498

Answer:

The function of this equation is: [tex]F(n)=\frac{1}{4}n^4-\frac{1}{3}n^3+n+C[/tex]

Step-by-step explanation:

Answer:

1, 5, 19, 49

Step-by-step explanation:

To obtain the first 4 terms substitute n = 1, 2, 3, 4 into f(n)

f(1) = 1³ - 1² + 1 = 1 - 1 + 1 = 1

f(2) = 2³ - 2² + 1 = 8 - 4 + 1 = 4 + 1 = 5

f(3) = 3³ - 3² + 1 = 27 - 9 + 1 = 18 + 1 = 19

f(4) = 4³ - 4² + 1 = 64 - 16 + 1 = 48 + 1 = 49

The first 4 terms are 1, 5, 19, 49

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