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3
Use the drawing tools) to form the correct answer on the provided graph
Plot the axis of symmetry and the point where the maximum value occurs for this function
x=+x+22-8
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3 Use The Drawing Tools To Form The Correct Answer On The Provided Graph Plot The Axis Of Symmetry And The Point Where The Maximum Value Occurs For This Functio class=

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kamilmatematik100504

  • To find the maximum value of the function, we need to know the vertex of the parabola
  • [tex]\large \boldsymbol {} \displaystyle ax^2+bx+c=0 \\\\ \boldsymbol{x_v=-\frac{b}{2a} } \\\\\\ \boldsymbol {y_v=ax_v+bx_v+c}[/tex]  

  • Where    [tex]\large \boldsymbol {x_v \ \ ; \ \ y_v}[/tex] - are the coordinates of the vertex of the parabola

  • [tex]\large \boldsymbol \displaystyle {} f(x)=-(x+2)^2+8 = -1\cdot x^2-4x+4 \\\\\\ \displaystyle x_v=-\frac{-4}{-2} =-2 \\\\\\y_v=-(-2+2)^2+8 =8[/tex]  

  • The graph in the attached file
View image kamilmatematik100504
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