Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Can someone please help me?​

Can Someone Please Help Me class=

Sagot :

Answer: X=7/3

Step-by-step explanation:

3

+

2

=

2

+

1

3

3

3x+2=2x+\frac{13}{3}

3x+2=2x+313​

Solve

1

Subtract

2

2

2

from both sides of the equation

3

+

2

=

2

+

1

3

3

3x+2=2x+\frac{13}{3}

3x+2=2x+313​

3

+

2

2

=

2

+

1

3

3

2

3x+2{\color{#c92786}{-2}}=2x+\frac{13}{3}{\color{#c92786}{-2}}

3x+2−2=2x+313​−2

2

Simplify

Subtract the numbers

Subtract the numbers

3

=

2

+

7

3

3x=2x+\frac{7}{3}

3x=2x+37​

3

Subtract

2

2x

2x

from both sides of the equation

3

=

2

+

7

3

3x=2x+\frac{7}{3}

3x=2x+37​

3

2

=

2

+

7

3

2

3x{\color{#c92786}{-2x}}=2x+\frac{7}{3}{\color{#c92786}{-2x}}

3x−2x=2x+37​−2x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

7

3

x=\frac{7}{3}

x=37​

Solution

=

7

  1. 3