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Sagot :
No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.
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La trayectoria del primero es:
[tex]-x + 2y - 100 = 0[/tex]
[tex]x_1 = 2y - 100[/tex]
Para el segundo, tiene-se que:
[tex]-x + 200 + 2y = 0[/tex]
[tex]x_2 = 2y + 200[/tex]
Igualando los valores de x:
[tex]x_1 = x_2[/tex]
[tex]2y - 100 = 2y + 200[/tex]
[tex]0y = 300[/tex]
No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.
Un problema similar es dado en https://brainly.com/question/24653364
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