kaslene07
Answered

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What is the 6th term in the sequence below?
4,-8, 16, -32,

Sagot :

shawndaleberry28

Answer:

āˆ’128

Step-by-step explanation:

danielgeyfman

Assuming the pattern continues...

Answer:

[tex]128[/tex]

Step-by-step explanation:

We see that this is a geometric series with common ratio [tex]-2[/tex].

So, the 6th term is the 4th term times [tex](-2)^2=2^2=4[/tex].

So, the answer is [tex]4(-32)=\boxed{128}[/tex] and we're done!

Note:

The closed form for this geometric series is [tex]4*(-2)^{n-1}[/tex], which means the nth term is always [tex]4*(-2)^{n-1}[/tex].

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