Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

The area beneath the normal density curve is separated into three regions by the values
and
. Set the mean of the normal density curve to 6.4, the standard deviation to 0.7, and the -value
of
to 6.7. First, determine the value of the area to the right of .

Place
so that it equally divides the area to the left of
. What is the -value
of ?


Sagot :

fichoh

The value of the area to the right of X > 6.7 calculated from the normal distribution principle is 0.334

Given the Parameters :

  • Mean, μ = 6.4
  • Standard deviation, σ = 0.7
  • X = 6.7

Using the Zscore formula for a normal distribution :

  • Zscore = (X - mean) / standard deviation

The Zscore, when X = 6.7

  • Zscore = (6.7 - 6.4) / 0.7 = 0.4286

The area to the right of the distribution :

  • P(Z > 0.4286) = 1 - P(Z < 0.4286)

Using a normal distribution table or calculator :

  • P(Z > 0.4286) = 1 - 0.66589 = 0.334

Therefore, the probability value of P(X < 6.7) is

  • P(Z > 0.4286) = 0.334

Learn more :https://brainly.com/question/8165716

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.