Answered

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Write an equation for a line in slope-intercept form that is perpendicular to the line y = 4x + 3 and passes through the point (-4, -2).

Sagot :

rspill6

Answer:  The equation of the line perpendicular to y = 4x + 3 and passes through the point (-4, -2) is y = -(1/4)x - 3.

Step-by-step explanation:  An line perpendicular to perpendicular to the line y = 4x + 3 would have a slope that is the negative inverse of the refernce line.  That would make the new line's slope -(1/4), the negative inverse of 4,

We can write the new new as y = -(1/4)x + b.  b, the y-intercept, is +3 in the original equation, but it will change for the new line.  We can calculate the new y-intercept by using the one point, (-4,-2) that we know is a solution for the equation (it falls on the line).

y = -(1/4)x + b

-2 = -(1/4)(-4) + b

-2 = 1+b

b = -3

The equation of the line perpendicular to y = 4x + 3 and passes through the point (-4, -2) is y = -(1/4)x - 3.

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