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Algebra 2 ............​

Algebra 2 class=

Sagot :

abidemiokin

The equation of the line through the point (-4, 7) and with a slope of -5/2 is y = -5/2x - 3

The equation of a line in slope intercept form is expressed as:

[tex]y-y_0 = m(x-x_0)[/tex]

m is the slope

(x0, y0) is the point on the line.

Given the following parameters:

m = -5/2 and (x0, y0) =(-4, 7)

Substitute the given coordinates into the formula above;

y  - 7 = -5/2(x + 4)

2(y-7) = -5(x+4)

2y-14 = -5x - 20

2y = -5x - 20  + 14

2y = -5x - 6

y = -5/2x - 3

Hence the equation of the line through the point (-4, 7) and with a slope of -5/2 is y = -5/2x - 3

Learn more here: https://brainly.com/question/17003809

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