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A batting machine uses an automatic baseball feeder. During baseball
practice the feeder is a full. An attendant fills it with 15 baseballs so
that the feeder is now full. How many baseballs does the feeder
hold when full?
A. Write an equation to represent the problem.


A Batting Machine Uses An Automatic Baseball Feeder During Baseball Practice The Feeder Is A Full An Attendant Fills It With 15 Baseballs So That The Feeder Is class=

Sagot :

The feeders in battling machine are represented in proportions and fractions.

  • The equation that represents the problem is: [tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]
  • The feeder can hold 30 baseballs, when full

The given parameters are:

[tex]\mathbf{Initial = \frac 16x}[/tex] ------ 1/6 full

[tex]\mathbf{Additional = 15}[/tex] --- baseballs added

[tex]\mathbf{Final = \frac 23x}[/tex] ---- 2/3 full

So, the equation that represents the problem is:

[tex]\mathbf{Initial + Additional = Final}[/tex]

So, we have:

[tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]

The number of baseballs it can hold is calculated as follows:

[tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]

Multiply through by 6

[tex]\mathbf{x + 90 = 4x}[/tex]

Collect like terms

[tex]\mathbf{4x - x = 90 }[/tex]

[tex]\mathbf{3x = 90 }[/tex]

Divide through by 3

[tex]\mathbf{x = 30 }[/tex]

Hence, the feeder can hold 30 baseballs, when full

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