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Sagot :
At 20°c, a 0.376 m aqueous solution of ammonium chloride has a density of 1.0045 g/ml. The mass percent of the ammonium chloride in the solution is 2.003%.
The number of moles of a substance can be estimated as:
[tex]\mathbf{number\ of\ moles = \dfrac{mass}{molar \ mass}}[/tex]
Given that:
- number of moles = 0.376 M
- molar mass of ammonium chloride = 53.50 g/ml
Mass = number of moles × molar mass
Mass = 0.376 × 53.50
Mass = 20.116 grams
In one mL of ammonium chloride; the grams of ammonium chloride is:
[tex]\mathbf{= \dfrac{20.116 \ grams}{1000 \ mL}}[/tex]
= 0.020116 g/mL
The mass of ammonium chloride in the solution can be computed as:
[tex]\mathbf{=(\dfrac{mass \ of \ NH_4Cl}{density \ of \ the \ solution})\times 100}[/tex]
[tex]\mathbf{=(\dfrac{0.020116 }{1.0045})\times 100}[/tex]
= 2.003%
Therefore, we can conclude that the mass percent of the ammonium chloride in the solution is 2.003%.
Learn more about ammonium chloride here:
https://brainly.com/question/23387600?referrer=searchResults
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