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Sagot :
[tex]\large\boxed{\mathsf{-4[x] + 10 = 50}}\\\large\boxed{\rightarrow\mathsf{-4x + 10 = 50}}\\\\\large\text{SUBTRACT 10 to BOTH SIDES}\\\large\boxed{\mathsf{-4x + 10 - 10 = 50 - 10}}\\\large\text{CANCEL out: 10 - 10 because that gives you 0}\\\large\text{KEEP: 50 - 10 because it helps solve for the x-value}\\\\\large\boxed{\mathsf{50 - 10 = \bf 40}}\\\large\boxed{\mathsf{-4x = 40}}\\\\\large\text{DIVIDE -4 to BOTH SIDES}\\\large\boxed{\mathsf{\dfrac{-4x}{4}=\dfrac{40}{-4}}}[/tex]
[tex]\large\text{CANCEL out: }\rm{\dfrac{-4}{-4}}\large\text{ because that gives you 1}\\\large\text{KEEP: }\rm{\dfrac{40}{-4}}\large\text{ because it gives you the x-value answer}\\\\\large\boxed{\mathsf{x = \dfrac{40}{-4}}}\\\\\large\text{SIMPLIFY IT AND YOU HAVE THE RESULT OF THE X! }\\\\\huge\boxed{\text{Therefore, your answer is: \textsf{x = -10}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\frak{Amphitrite1040:)}[/tex]
Step-by-step explanation:
[tex] \bf \underline{Given-} \\ [/tex]
[tex] \sf{ - 4(x) + 10 = 50} \\ [/tex]
[tex] \bf \underline{To \: find-} \\ [/tex]
[tex] \sf{ \:the \: value \: of \: x = \: ? } \\ [/tex]
[tex] \bf \underline{Solution-} \\ [/tex]
[tex]\textsf{Given equation,}\\[/tex]
[tex] \sf{ - 4(x) + 10 = 50} \\ [/tex]
- Now, multiply -4 from (x) to get -4x.
[tex] \sf{ \Rightarrow \: - 4x + 10 = 50 } \\ [/tex]
- Now, +10 will move to RHS then it's sign will be charged -10
[tex] \sf{ \Rightarrow \: - 4x = 50 - 10} \\ [/tex]
- Subtract 50 from -10 to get 40. Because 50 is greater than -10.
[tex] \sf{ \Rightarrow \: - 4x = 40 } \\ [/tex]
[tex] \sf{ \Rightarrow \: x = \cancel\frac{ - {40}^{- 10 }}{4}} \\ [/tex]
[tex] { \: \therefore \: \underline{ \boxed{{ \sf{x = - 10.}}}}}[/tex]
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