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a cylindrical tank with radius 7 m is being filled with water at a rate of 4 m3/min. how fast is the height of the water increasing?

Sagot :

Answer:

0.026 m / min.

Step-by-step explanation:

Volume V = π7^2h

V = 49πh

dV/dh = 49π

Rate that the volume is increasing is 4 m3/min.

So dV/dt = 4

dV/dt = dh/dt * dV/dh

4 = dh/dt * 49π

dh/dt = 4/49π

= 0.026 m / min.