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solve this equation 8+8x=8

Sagot :

Hello!

Answer:

x=0

Step-by-step explanation:

Hope this helps!

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Answer:  The correct answer is:  " x = 0 " .

________

Step-by-step explanation:

Given:  " 8 + 8x = 8 " ;  Solve for "x" ;

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Method 1)

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Subtract "8" from each side of the equation:

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  → " 8 + 8x − 8 = 8 − 8 " ;

  → On the "left-hand side" of the equation:

          Note the following "like terms" :

            " +8 − 8 = 0 " ;

  →  and we are left with "8x" on the "left-hand side" of the equation.

  → On the "right hand side" of the equation:

         The "(8 − 8)" = 0 ;

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And we are left with:

  →  " 8x = 0 " ;

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Now, divide each side of the equation by "8" ;

   to isolate "x" on one side of the equation;

   & to solve for "x" :

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  →  8x / 8 =  0/8 ;

to get:

  →  " x = 0 " ;

  →  which is the correct answer.

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Method 2)

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Given:  " 8 + 8x = 8 " ;  Solve for "x" ;

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Subtract "8" from each side of the equation; in the following manner:

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   8  +  8x    =    8 ;

 - 8             =   - 8 ;

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   0  +  8x    =    0 ;

→ We have:  " 0 + 8x = 0 " ;

Note: On the "left-hand side" ; we have:

                 " 0 + 8x " ;

  We can simplify this to "8x" ; since the "addition property of zero" states that when "0" is added to any value; the resulting value does not change.

Now, we can bring down the "0" from the "right-hand side" of the equation;

And we can rewrite our equation as:

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   → " 8x = 0 " ;

Now, divide each side of the equation by "8" ;

   to isolate "x" on one side of the equation;

   & to solve for "x" :

________

  →  8x / 8 =  0/8 ;

to get:

  →  " x = 0 " ;

  →  which is the correct answer.

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Method 3)

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Given:  " 8 + 8x = 8 " ;  Solve for "x" ;

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Divide each side of the equation by "8" ;

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  → " [tex]\frac{(8 + 8x)}{8} =\frac{8}{8}[/tex] " ;

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To solve:

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Note: On the "right-hand side" of the equation:

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Take note that: " [tex]\frac{8}{8} =[/tex] (8 ÷ 8) = 1 " ;

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Rewrite the equation as:

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 →  " [tex]\frac{(8 + 8x)}{8} =1[/tex]  "  ;

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To solve:

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Note:  " [tex]\frac{x}{y} = z[/tex] " ;  ↔ [tex]x = z*y[/tex] ; [tex](y\neq 0)[/tex] ;

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 →  " [tex]\frac{(8 + 8x)}{8} =1[/tex]  "  ;  

 →  From the "left-hand side" of the equation;

      Let us simplify:

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 →  " [tex]\frac{(8 + 8x)}{8} = \frac{8}{8} + \frac{8x}{8} = 1 + x[/tex] " ;  

Now, bring down the "1" from the "right-hand side" of the equation;

and rewrite the equation:

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 →  " 1 + x = 1 " ;

Now, subtract "1" from each side of the equation;

   to isolate "x" on one side of the equation;

   & to solve for "x" :

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     " 1 + x − 1 = 1 − 1 " ;

  → On the "left-hand side" of the equation:

          Note the following "like terms" :

            +1 − 1 = 0 " ;

  →  and we are left with "x" on the "left-hand side" of the equation.

  → On the "right hand side" of the equation:

         The "(1 − 1)" = 0 ;

  → And we are left with:

      →  " x = 0 " ;

      → which is the correct answer!

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The correct answer is:  " x = 0 " .

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Hope that this answer—and the corresponding explanations—

are helpful !

  WIshing you the best!

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