Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Seventy-five percent of consumers prefer to purchase electronics online. You randomly select 8 consumers. Find the probability that the number of consumers who prefer to

purchase electronics online is (a) exactly five, (b) more than five, and (c) at most five.

(a) Find the probability that the number that prefer to purchase electronics online is exactly five.

P(5)=

(Round to three decimal places as needed.)

Sagot :

fichoh

Using the binomial probability relation, the probability of the following events are :

  • P(x = 5) = 0.2076
  • P(x > 5) = 0.6785
  • P(x ≤ 5) = 0.3215

Using the relation :

P(x = x) = nCx * p^x * q^(n-x)

  • Probability of success, p = 0.75
  • q = 1 - p = 1 - 0.75 = 0.25
  • Number of trials, n = 8

Probability of exactly 5 :

P(x = 5) = 8C5 × 0.75^5 × 0.25^3

P(x = 5) = 0.2076

2.) Probability of selecting more than 5 :

P(x > 5) = p(6) + p(7) + p(8)

Using a binomial probability calculator :

P(x > 5) = 0.6785

3.)

Probability at most 5 :

P(x ≤ 5) = p(0) + p(1) + p(2) + p(3) + p(4) + p(5)

Using a binomial probability calculator :

P(x ≤ 5) = 0.3215

Therefore, the probability of selecting at most 5 is 0.3215

Learn more :https://brainly.com/question/12474772

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.