nataliaacuadra
Answered

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i need help with algebra 2 pleasee

I Need Help With Algebra 2 Pleasee class=

Sagot :

danielgeyfman

Answer:

[tex]x=\pm \sqrt{21}/7[/tex]

Step-by-step explanation:

We can add 9 to both sides of the equation to get [tex]21x^2=9[/tex].

We can divide both sides of the equation by 21 to get [tex]x^2=9/21[/tex].

We take the square root of both sides of the equation to get [tex]x=\pm \sqrt{9/21}[/tex].

However, that isn't in the form we need.

We know that [tex]\sqrt{9/21}=\sqrt{9}/\sqrt{21}=3/\sqrt{21}=3\sqrt{21}/(\sqrt{21}*\sqrt{21})=3\sqrt{21}/21=\sqrt{21}/7[/tex]

so the answer is really [tex]x=\pm \sqrt{21}/7[/tex] and we're done!

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